Consider the situation shown in the figure. T | vedclass

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(A) The wire $PQ$ moves with a constant velocity $v = 5 \, cm/s = 0.05 \, m/s$ in a uniform magnetic field $B = 1.0 \, T$.When the switch $S$ is conne

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(A) The wire $PQ$ moves with a constant velocity $v = 5 \, cm/s = 0.05 \, m/s$ in a uniform magnetic field $B = 1.0 \, T$.When the switch $S$ is connected to the middle rail, the circuit is completed through the top rail and the middle rail.The length of the wire $PQ$ between the top rail and the middle rail is $\ell = 2 \, cm = 0.02 \, m$.The induced electromotive force (emf) in this segment is given by $\varepsilon = B v \ell$.Substituting the values: $\varepsilon = 1.0 	imes 0.05 	imes 0.02 = 0.001 \, V = 1 \, mV$.The current $I$ in the $10 \, \Omega$ resistor is $I = \frac{\varepsilon}{R} = \frac{1 	imes 10^{-3} \, V}{10 \, \Omega} = 10^{-4} \, A = 0.1 \, mA$.

Consider the situation shown in the figure. The wire $PQ$ has a negligible resistance and is made to slide on the three rails with a constant speed of $5 \, cm/s$. Find the current in the $10 \, \Omega$ resistor when the switch $S$ is connected to the middle rail. (Given: $B = 1.0 \, T$) (in $mA$)

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